Za funkcijo
f
(
x
,
y
,
z
)
{\displaystyle f(x,y,z)\!\,}
v trirazsežnih kartezičnih koordinatnih spremenljivkah je gradient vektorsko polje :
grad
(
f
)
≡
∇
f
≡
∇
→
f
=
(
∂
∂
x
,
∂
∂
y
,
∂
∂
z
)
f
=
∂
f
∂
x
i
^
+
∂
f
∂
y
j
^
+
∂
f
∂
z
k
^
{\displaystyle \operatorname {grad} (f)\equiv \nabla f\equiv \mathbf {\vec {\nabla }} f={\begin{pmatrix}\displaystyle {\frac {\partial }{\partial x}},\ {\frac {\partial }{\partial y}},\ {\frac {\partial }{\partial z}}\end{pmatrix}}f={\frac {\partial f}{\partial x}}\mathbf {\hat {i}} +{\frac {\partial f}{\partial y}}\mathbf {\hat {j}} +{\frac {\partial f}{\partial z}}\mathbf {\hat {k}} \!\,}
kjer so
i
^
{\displaystyle \mathbf {\hat {i}} \!\,}
,
j
^
{\displaystyle \mathbf {\hat {j}} \!\,}
in
k
^
{\displaystyle \mathbf {\hat {k}} \!\,}
standardni enotski vektorji za osi
x
{\displaystyle x\!\,}
,
y
{\displaystyle y\!\,}
in
z
{\displaystyle z\!\,}
. Bolj splošno, za funkcijo
n
{\displaystyle n\!\,}
spremenljivk
ψ
(
x
1
,
…
,
x
n
)
{\displaystyle \psi (x_{1},\ldots ,x_{n})\!\,}
, imenovano tudi skalarno polje , je gradient vektorsko polje:
∇
→
ψ
=
(
∂
∂
x
1
,
…
,
∂
∂
x
n
)
ψ
=
∂
ψ
∂
x
1
e
^
1
+
⋯
+
∂
ψ
∂
x
n
e
^
n
,
{\displaystyle \mathbf {\vec {\nabla }} \psi ={\begin{pmatrix}\displaystyle {\frac {\partial }{\partial x_{1}}},\ldots ,{\frac {\partial }{\partial x_{n}}}\end{pmatrix}}\psi ={\frac {\partial \psi }{\partial x_{1}}}\mathbf {\hat {e}} _{1}+\dots +{\frac {\partial \psi }{\partial x_{n}}}\mathbf {\hat {e}} _{n}\!\,,}
kjer so
e
^
i
(
i
=
1
,
2
,
…
,
n
)
{\displaystyle \mathbf {\hat {e}} _{i}\,(i=1,2,\ldots ,n)\!\,}
med seboj ortogonalni enotski vektorji.
Kot pove že ime, je gradient sorazmeren z najhitrejšo (pozitivno) spremembo funkcije in kaže v smeri te spremembe.
Za vektorsko polje
A
→
=
(
A
1
,
…
,
A
n
)
{\displaystyle \mathbf {\vec {A}} =\left(A_{1},\ldots ,A_{n}\right)\!\,}
, imenovano tudi tenzorsko polje prvega reda, je gradient ali totalni odvod Jakobijeva matrika
n
×
n
{\displaystyle n\times n\!\,}
:[ 1] :404
J
→
A
→
=
d
A
→
=
(
∇
→
A
→
)
⊤
=
(
∂
A
i
∂
x
j
)
i
j
.
{\displaystyle \mathbf {\vec {J}} _{\mathbf {\vec {A}} }=\operatorname {d} \!\mathbf {\vec {A}} =(\mathbf {\vec {\nabla }} \!\mathbf {\vec {A}} )^{\top }=\left({\frac {\partial A_{i}}{\partial x_{j}}}\right)_{\!ij}\!\,.}
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
poljubnega reda
k
{\displaystyle k\!\,}
, je gradient
grad
(
T
)
=
d
T
=
(
∇
T
)
⊤
{\displaystyle \operatorname {grad} (\mathbf {T} )=\operatorname {d} \!\mathbf {T} =(\nabla \mathbf {T} )^{\top }\!\,}
tenzorsko polje reda
k
+
1
{\displaystyle k+1\!\,}
.
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
reda
k
>
0
{\displaystyle k>0\!\,}
, je tenzorsko polje
∇
T
{\displaystyle \nabla \mathbf {T} \!\,}
reda
k
+
1
{\displaystyle k+1\!\,}
definirano kot rekurzivna relacija :
(
∇
T
)
⋅
c
→
=
∇
(
T
⋅
c
→
)
,
{\displaystyle (\nabla \mathbf {T} )\cdot \mathbf {\vec {c}} =\nabla (\mathbf {T} \cdot \mathbf {\vec {c}} )\!\,,}
kjer je
c
→
{\displaystyle \mathbf {\vec {c}} \!\,}
poljubni konstantni vektor .
Glavni članek: divergenca .
V kartezičnih koordinatah je divergenca zvezno odvedljivega vektorskega polja
F
→
=
F
x
i
^
+
F
y
j
^
+
F
z
k
^
{\displaystyle \mathbf {\vec {F}} =F_{x}\mathbf {\hat {i}} +F_{y}\mathbf {\hat {j}} +F_{z}\mathbf {\hat {k}} \!\,}
skalarna funkcija :
div
F
→
≡
∇
⋅
F
→
=
(
∂
∂
x
,
∂
∂
y
,
∂
∂
z
)
⋅
(
F
x
,
F
y
,
F
z
)
=
∂
F
x
∂
x
+
∂
F
y
∂
y
+
∂
F
z
∂
z
.
{\displaystyle {\begin{aligned}\operatorname {div} \mathbf {\vec {F}} \equiv \nabla \cdot \mathbf {\vec {F}} &={\begin{pmatrix}{\dfrac {\partial }{\partial x}},\ {\dfrac {\partial }{\partial y}},\ {\dfrac {\partial }{\partial z}}\end{pmatrix}}\cdot {\begin{pmatrix}F_{x},\ F_{y},\ F_{z}\end{pmatrix}}\\[1ex]&={\frac {\partial F_{x}}{\partial x}}+{\frac {\partial F_{y}}{\partial y}}+{\frac {\partial F_{z}}{\partial z}}\!\,.\end{aligned}}}
Kot pove že ime, je divergenca (krajevna) mera stopnje razhajanja vektorjev v polju.
Divergenca tenzorskega polja
T
{\displaystyle \mathbf {T} \!\,}
neničelnega reda
k
{\displaystyle k\!\,}
je zapisana kot
div
(
T
)
≡
∇
⋅
T
{\displaystyle \operatorname {div} (\mathbf {T} )\equiv \nabla \cdot \mathbf {T} \!\,}
, kar je kontrakcija tenzorskega polja reda
k
−
1
{\displaystyle k-1\!\,}
. Natančneje, divergenca vektorja je skalar . Divergenco tenzorskega polja višjega reda se lahko najde z razstavitvijo tenzorskega polja v vsoto zunanjih produktov in rabo identitete:
∇
⋅
(
A
⊗
T
)
=
T
(
∇
⋅
A
)
+
(
A
⋅
∇
)
T
,
{\displaystyle \nabla \cdot \left(\mathbf {A} \otimes \mathbf {T} \right)=\mathbf {T} (\nabla \cdot \mathbf {A} )+(\mathbf {A} \cdot \nabla )\mathbf {T} \!\,,}
kjer je
A
⋅
∇
{\displaystyle \mathbf {A} \cdot \nabla \!\,}
smerni odvod v smeri
A
{\displaystyle \mathbf {A} \!\,}
, pomnožen z njegovo velikostjo. Natančneje, za zunanji produkt dveh vektorjev:[ 1] :407
∇
⋅
(
A
→
B
→
⊤
)
=
B
→
(
∇
⋅
A
→
)
+
(
A
→
⋅
∇
)
B
→
.
{\displaystyle \nabla \cdot \left(\mathbf {\vec {A}} \mathbf {\vec {B}} ^{\top }\right)=\mathbf {\vec {B}} (\nabla \cdot \mathbf {\vec {A}} )+(\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} \!\,.}
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
reda
k
>
1
{\displaystyle k>1\!\,}
je tenzorsko polje
∇
⋅
T
{\displaystyle \nabla \cdot \mathbf {T} \!\,}
reda
k
−
1
{\displaystyle k-1\!\,}
definirano z rekurzivno relacijo:
(
∇
⋅
T
)
⋅
c
→
=
∇
⋅
(
T
⋅
c
→
)
{\displaystyle (\nabla \cdot \mathbf {T} )\cdot \mathbf {\vec {c}} =\nabla \cdot (\mathbf {T} \cdot \mathbf {\vec {c}} )\!\,}
kjer je
c
→
{\displaystyle \mathbf {\vec {c}} }
poljubni konstantni vektor.
V kartezičnih koordinatah je rotor vektorskega polja
F
→
=
F
x
i
^
+
F
y
j
^
+
F
z
k
^
{\displaystyle \mathbf {\vec {F}} =F_{x}\mathbf {\hat {i}} +F_{y}\mathbf {\hat {j}} +F_{z}\mathbf {\hat {k}} \!\,}
vektorsko polje:
curl
F
≡=
∇
×
F
→
=
(
∂
∂
x
,
∂
∂
y
,
∂
∂
z
)
×
(
F
x
,
F
y
,
F
z
)
=
|
i
^
j
^
k
^
∂
∂
x
∂
∂
y
∂
∂
z
F
x
F
y
F
z
|
=
(
∂
F
z
∂
y
−
∂
F
y
∂
z
)
i
^
+
(
∂
F
x
∂
z
−
∂
F
z
∂
x
)
j
^
+
(
∂
F
y
∂
x
−
∂
F
x
∂
y
)
k
^
,
{\displaystyle {\begin{aligned}\operatorname {curl} \mathbf {F} \equiv =\nabla \times \mathbf {\vec {F}} &={\begin{pmatrix}\displaystyle {\frac {\partial }{\partial x}},\ {\frac {\partial }{\partial y}},\ {\frac {\partial }{\partial z}}\end{pmatrix}}\times {\begin{pmatrix}F_{x},\ F_{y},\ F_{z}\end{pmatrix}}\\[1em]&={\begin{vmatrix}\mathbf {\hat {i}} &\mathbf {\hat {j}} &\mathbf {\hat {k}} \\{\frac {\partial }{\partial x}}&{\frac {\partial }{\partial y}}&{\frac {\partial }{\partial z}}\\F_{x}&F_{y}&F_{z}\end{vmatrix}}\\[1em]&=\left({\frac {\partial F_{z}}{\partial y}}-{\frac {\partial F_{y}}{\partial z}}\right)\mathbf {\hat {i}} +\left({\frac {\partial F_{x}}{\partial z}}-{\frac {\partial F_{z}}{\partial x}}\right)\mathbf {\hat {j}} +\left({\frac {\partial F_{y}}{\partial x}}-{\frac {\partial F_{x}}{\partial y}}\right)\mathbf {\hat {k}} \!\,,\end{aligned}}}
kjer so
i
^
{\displaystyle \mathbf {\hat {i}} \!\,}
,
j
^
{\displaystyle \mathbf {\hat {j}} \!\,}
in
k
^
{\displaystyle \mathbf {\hat {k}} \!\,}
enotski vektorji za osi
x
{\displaystyle x\!\,}
,
y
{\displaystyle y\!\,}
in
z
{\displaystyle z\!\,}
.
Kot pove že ime, je rotor mera, za koliko bližnji vektorji težijo v krožni smeri.
V Einsteinovem zapisu ima vektorsko polje
F
→
=
(
F
1
,
F
2
,
F
3
)
{\displaystyle \mathbf {\vec {F}} ={\begin{pmatrix}F_{1},\ F_{2},\ F_{3}\end{pmatrix}}\!\,}
rotor, podan kot:
∇
×
F
→
=
ε
i
j
k
e
^
i
∂
F
k
∂
x
j
,
{\displaystyle \nabla \times \mathbf {\vec {F}} =\varepsilon ^{ijk}\mathbf {\hat {e}} _{i}{\frac {\partial F_{k}}{\partial x_{j}}}\!\,,}
kjer je
ε
=
±
1
{\displaystyle \varepsilon =\pm 1\!\,}
ali
0
{\displaystyle 0\!\,}
Levi-Civitajev simbol parnosti (permutacije) .
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
reda
k
>
1
{\displaystyle k>1\!\,}
je tenzorsko polje
∇
×
T
{\displaystyle \nabla \times \mathbf {T} \!\,}
reda
k
{\displaystyle k\!\,}
definirano z rekurzivno relacijo:
(
∇
×
T
)
⋅
c
→
=
∇
×
(
T
⋅
c
→
)
,
{\displaystyle (\nabla \times \mathbf {T} )\cdot \mathbf {\vec {c}} =\nabla \times (\mathbf {T} \cdot \mathbf {\vec {c}} )\!\,,}
kjer je
c
→
{\displaystyle \mathbf {\vec {c}} \!\,}
poljubni konstantni vektor.
Tenzorsko polje reda večjega od ena se lahko razstavi v vsoto zunanjih produktov, nato pa se lahko rabi naslednjo identiteto:
∇
×
(
A
⊗
T
)
=
(
∇
×
A
)
⊗
T
−
A
×
(
∇
T
)
.
{\displaystyle \nabla \times \left(\mathbf {A} \otimes \mathbf {T} \right)=(\nabla \times \mathbf {A} )\otimes \mathbf {T} -\mathbf {A} \times (\nabla \mathbf {T} )\!\,.}
Še posebej za zunanji produkt dveh vektorjev:[ 1] :407
∇
×
(
A
→
B
→
⊤
)
=
(
∇
×
A
→
)
B
→
⊤
−
A
→
×
(
∇
B
→
)
.
{\displaystyle \nabla \times \left(\mathbf {\vec {A}} \mathbf {\vec {B}} ^{\top }\right)=(\nabla \times \mathbf {\vec {A}} )\mathbf {\vec {B}} ^{\top }-\mathbf {\vec {A}} \times (\nabla \mathbf {\vec {B}} )\!\,.}
V kartezični koordinatah je Laplaceov operator funkcije
f
(
x
,
y
,
z
)
{\displaystyle f(x,y,z)\!\,}
:
Δ
f
≡
∇
2
f
≡
(
∇
⋅
∇
)
f
=
∂
2
f
∂
x
2
+
∂
2
f
∂
y
2
+
∂
2
f
∂
z
2
.
{\displaystyle \Delta f\equiv \nabla ^{2}\!f\equiv (\nabla \cdot \nabla )f={\frac {\partial ^{2}\!f}{\partial x^{2}}}+{\frac {\partial ^{2}\!f}{\partial y^{2}}}+{\frac {\partial ^{2}\!f}{\partial z^{2}}}\!\,.}
Laplaceov opeartor je mera, koliko se funkcija spreminja na majhni sferi s središčem v točki.
Ko je Laplaceov operator enak 0, se funkcija imenuje harmonična funkcija . To pomeni:
Δ
f
=
0
.
{\displaystyle \Delta f=0\!\,.}
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
se Laplaceov operator v splošnem zapiše kot:
Δ
T
=
∇
2
T
=
(
∇
⋅
∇
)
T
{\displaystyle \Delta \mathbf {T} =\nabla ^{2}\mathbf {T} =(\nabla \cdot \nabla )\mathbf {T} \!\,}
in je tenzorsko polje istega reda.
Za tenzorsko polje
T
{\displaystyle \mathbf {T} \!\,}
reda
k
>
0
{\displaystyle k>0\!\,}
je tenzorsko polje
∇
2
T
{\displaystyle \nabla ^{2}\mathbf {T} \!\,}
reda
k
{\displaystyle k\!\,}
definirano z rekurzivno relacijo:
(
∇
2
T
)
⋅
c
→
=
∇
2
(
T
⋅
c
→
)
,
{\displaystyle \left(\nabla ^{2}\mathbf {T} \right)\cdot \mathbf {\vec {c}} =\nabla ^{2}(\mathbf {T} \cdot \mathbf {\vec {c}} )\!\,,}
kjer je
c
→
{\displaystyle \mathbf {\vec {c}} \!\,}
poljubni konstantni vektor.
V Feynmanovem podpisnem zapisu :
∇
B
(
A
⋅
B
)
=
A
×
(
∇
×
B
)
+
(
A
⋅
∇
)
B
,
{\displaystyle \nabla _{\mathbf {B} }\!\left(\mathbf {A{\cdot }B} \right)=\mathbf {A} {\times }\!\left(\nabla {\times }\mathbf {B} \right)+\left(\mathbf {A} {\cdot }\nabla \right)\mathbf {B} \!\,,}
kjer zapis
∇
B
{\displaystyle \nabla _{\mathbf {B} }\!\,}
pomeni, da podpisani gradient deluje samo na faktorju
B
{\displaystyle \mathbf {B} \!\,}
.[ 2] :105–106, 120–123 [ 3] [ 4]
Bolj splošen, a podoben je Hestenesov zapis z nadpisno piko v geometrijski algebri .[ 2] :227–228 [ 5] Zgornja identiteta se nato izrazi kot:
∇
˙
(
A
→
⋅
B
→
˙
)
=
A
→
×
(
∇
×
B
→
)
+
(
A
→
⋅
∇
)
B
→
,
{\displaystyle {\dot {\nabla }}\left(\mathbf {\vec {A}} {\cdot }{\dot {\mathbf {\vec {B}} }}\right)=\mathbf {\vec {A}} {\times }\!\left(\nabla {\times }\mathbf {\vec {B}} \right)+\left(\mathbf {\vec {A}} {\cdot }\nabla \right)\mathbf {\vec {B}} \!\,,}
kjer nadpisne pike definirajo obseg vektorskega odvoda. Vektor s piko, v tem primeru
B
→
{\displaystyle \mathbf {\vec {B}} \!\,}
, se odvaja, medtem ko
A
→
{\displaystyle \mathbf {\vec {A}} \!\,}
(brez pike) ostane konstanten.
Uporabnost Feynmanovega podpisnega zapisa je v njegovi rabi pri izpeljavi identitet vektorskih in tenzorskih odvodov, kot v naslednjem primeru, ki rabi algebrsko identiteto
C
→
⋅
(
A
→
×
B
→
)
=
(
C
→
×
A
→
)
⋅
B
→
{\displaystyle \mathbf {\vec {C}} \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )=(\mathbf {\vec {C}} \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} \!\,}
:
∇
⋅
(
A
→
×
B
→
)
=
∇
A
→
⋅
(
A
→
×
B
→
)
+
∇
B
→
⋅
(
A
→
×
B
→
)
=
(
∇
A
→
×
A
→
)
⋅
B
→
+
(
∇
B
→
×
A
→
)
⋅
B
→
=
(
∇
A
→
×
A
→
)
⋅
B
→
−
(
A
→
×
∇
B
→
)
⋅
B
→
=
(
∇
A
→
×
A
→
)
⋅
B
→
−
A
→
⋅
(
∇
B
→
×
B
→
)
=
(
∇
×
A
→
)
⋅
B
→
−
A
→
⋅
(
∇
×
B
→
)
.
{\displaystyle {\begin{aligned}\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )&=\nabla _{\mathbf {\vec {A}} }\cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )+\nabla _{\mathbf {\vec {B}} }\cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\\[2pt]&=(\nabla _{\mathbf {\vec {A}} }\times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} +(\nabla _{\mathbf {\vec {B}} }\times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} \\[2pt]&=(\nabla _{\mathbf {\vec {A}} }\times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -(\mathbf {\vec {A}} \times \nabla _{\mathbf {\vec {B}} })\cdot \mathbf {\vec {B}} \\[2pt]&=(\nabla _{\mathbf {\vec {A}} }\times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -\mathbf {\vec {A}} \cdot (\nabla _{\mathbf {\vec {B}} }\times \mathbf {\vec {B}} )\\[2pt]&=(\nabla \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -\mathbf {\vec {A}} \cdot (\nabla \times \mathbf {\vec {B}} )\!\,.\end{aligned}}}
Alternativna metoda je raba kartezičnih komponent operatorja nabla na naslednji način (z implicitnim seštevanjem po indeksu
i
{\displaystyle i\!\,}
):
∇
⋅
(
A
→
×
B
→
)
=
e
^
i
∂
i
⋅
(
A
→
×
B
→
)
=
e
^
i
⋅
∂
i
(
A
→
×
B
→
)
=
e
^
i
⋅
(
∂
i
A
→
×
B
→
+
A
→
×
∂
i
B
→
)
=
e
^
i
⋅
(
∂
i
A
→
×
B
→
)
+
e
^
i
⋅
(
A
→
×
∂
i
B
→
)
=
(
e
^
i
×
∂
i
A
→
)
⋅
B
→
+
(
e
^
i
×
A
→
)
⋅
∂
i
B
→
=
(
e
^
i
×
∂
i
A
→
)
⋅
B
→
−
(
A
→
×
e
^
i
)
⋅
∂
i
B
→
=
(
e
^
i
×
∂
i
A
→
)
⋅
B
→
−
A
→
⋅
(
e
^
i
×
∂
i
B
→
)
=
(
e
^
i
∂
i
×
A
→
)
⋅
B
→
−
A
→
⋅
(
e
^
i
∂
i
×
B
→
)
=
(
∇
×
A
→
)
⋅
B
→
−
A
→
⋅
(
∇
×
B
→
)
.
{\displaystyle {\begin{aligned}\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )&=\mathbf {\hat {e}} _{i}\partial _{i}\cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\\[2pt]&=\mathbf {\hat {e}} _{i}\cdot \partial _{i}(\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\\[2pt]&=\mathbf {\hat {e}} _{i}\cdot (\partial _{i}\mathbf {\vec {A}} \times \mathbf {\vec {B}} +\mathbf {\vec {A}} \times \partial _{i}\mathbf {\vec {B}} )\\[2pt]&=\mathbf {\hat {e}} _{i}\cdot (\partial _{i}\mathbf {\vec {A}} \times \mathbf {\vec {B}} )+\mathbf {\hat {e}} _{i}\cdot (\mathbf {\vec {A}} \times \partial _{i}\mathbf {\vec {B}} )\\[2pt]&=(\mathbf {\hat {e}} _{i}\times \partial _{i}\mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} +(\mathbf {\hat {e}} _{i}\times \mathbf {\vec {A}} )\cdot \partial _{i}\mathbf {\vec {B}} \\[2pt]&=(\mathbf {\hat {e}} _{i}\times \partial _{i}\mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -(\mathbf {\vec {A}} \times \mathbf {\hat {e}} _{i})\cdot \partial _{i}\mathbf {\vec {B}} \\[2pt]&=(\mathbf {\hat {e}} _{i}\times \partial _{i}\mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -\mathbf {\vec {A}} \cdot (\mathbf {\hat {e}} _{i}\times \partial _{i}\mathbf {\vec {B}} )\\[2pt]&=(\mathbf {\hat {e}} _{i}\partial _{i}\times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -\mathbf {\vec {A}} \cdot (\mathbf {\hat {e}} _{i}\partial _{i}\times \mathbf {\vec {B}} )\\[2pt]&=(\nabla \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -\mathbf {\vec {A}} \cdot (\nabla \times \mathbf {\vec {B}} )\!\,.\end{aligned}}}
Druga metoda za izpeljavo identitet vektorskih in tenzorskih odvodov je zamenjava vseh pojavitev vektorja v algebrski identiteti z operatorjem nabla, pod pogojem, da se nobena spremenljivka ne pojavi hkrati znotraj in zunaj obsega operatorja ali hkrati znotraj obsega enega operatorja v izrazu in zunaj obsega drugega operatorja v istem izrazu (tj. operatorji morajo biti ugnezdeni). Veljavnost tega pravila izhaja iz veljavnosti Feynmanove metode, saj se lahko vedno nadomesti podpisani operator nabla in nato takoj izpusti podpisani indeks pod pogojem pravila. Na primer, iz identitete
A
→
⋅
(
B
→
×
C
→
)
=
(
A
→
×
B
→
)
⋅
C
→
{\displaystyle \mathbf {\vec {A}} \cdot (\mathbf {\vec {B}} \times \mathbf {\vec {C}} )=(\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\cdot \mathbf {\vec {C}} \!\,}
se lahko izpelje
A
→
⋅
(
∇
×
C
→
)
=
(
A
→
×
∇
)
⋅
C
→
{\displaystyle \mathbf {\vec {A}} \cdot (\nabla \times \mathbf {\vec {C}} )=(\mathbf {\vec {A}} \times \nabla )\cdot \mathbf {\vec {C}} \!\,}
, ne pa
∇
⋅
(
B
→
×
C
→
)
=
(
∇
×
B
→
)
⋅
C
→
{\displaystyle \nabla \cdot (\mathbf {\vec {B}} \times \mathbf {\vec {C}} )=(\nabla \times \mathbf {\vec {B}} )\cdot \mathbf {\vec {C}} \!\,}
, niti se iz
A
→
⋅
(
B
→
×
A
→
)
=
0
{\displaystyle \mathbf {\vec {A}} \cdot (\mathbf {\vec {B}} \times \mathbf {\vec {A}} )=0\!\,}
ne da izpeljati
A
→
⋅
(
∇
×
A
→
)
=
0
{\displaystyle \mathbf {\vec {A}} \cdot (\nabla \times \mathbf {\vec {A}} )=0\!\,}
. Po drugi strani pa podpisani operator nabla deluje na vseh pojavitvah podpisanega indeksa v členu, tako da
A
→
⋅
(
∇
A
→
×
A
→
)
=
∇
A
→
⋅
(
A
→
×
A
→
)
=
∇
⋅
(
A
→
×
A
→
)
=
0
{\displaystyle \mathbf {\vec {A}} \cdot (\nabla _{\mathbf {\vec {A}} }\times \mathbf {\vec {A}} )=\nabla _{\mathbf {\vec {A}} }\cdot (\mathbf {\vec {A}} \times \mathbf {\vec {A}} )=\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {A}} )=0\!\,}
. Prav tako se iz
A
→
×
(
A
→
×
C
→
)
=
A
→
(
A
→
⋅
C
→
)
−
(
A
→
⋅
A
→
)
C
→
{\displaystyle \mathbf {\vec {A}} \times (\mathbf {\vec {A}} \times \mathbf {\vec {C}} )=\mathbf {\vec {A}} (\mathbf {\vec {A}} \cdot \mathbf {\vec {C}} )-(\mathbf {\vec {A}} \cdot \mathbf {\vec {A}} )\mathbf {\vec {C}} \!\,}
lahko izpelje
∇
×
(
∇
×
C
→
)
=
∇
→
(
∇
⋅
C
→
)
−
∇
→
2
C
→
{\displaystyle \nabla \times (\nabla \times \mathbf {\vec {C}} )=\mathbf {\vec {\nabla }} (\nabla \cdot \mathbf {\vec {C}} )-\mathbf {\vec {\nabla }} ^{2}\mathbf {\vec {C}} \!\,}
, vendar se iz
(
A
→
ψ
)
⋅
(
A
→
ϕ
)
=
(
A
→
⋅
A
→
)
(
ψ
ϕ
)
{\displaystyle (\mathbf {\vec {A}} \psi )\cdot (\mathbf {\vec {A}} \phi )=(\mathbf {\vec {A}} \cdot \mathbf {\vec {A}} )(\psi \phi )\!\,}
morda ne bo dalo izpeljati
(
∇
→
ψ
)
⋅
(
∇
→
ϕ
)
=
∇
→
2
(
ψ
ϕ
)
{\displaystyle (\mathbf {\vec {\nabla }} \psi )\cdot (\mathbf {\vec {\nabla }} \phi )=\mathbf {\vec {\nabla }} ^{2}(\psi \phi )\!\,}
.
Podpisani indeks
c
{\displaystyle c\!\,}
na količini pomeni, da se začasno šteje za konstanto. Ker konstanta ni spremenljivka, se jo lahko, ko se uporabi pravilo zamenjave (glej prejšnji odstavek), za razliko od spremenljivke premakne v obseg operatorja nabla ali zunaj njega, kot v naslednjem primeru:[ 6]
∇
⋅
(
A
→
×
B
→
)
=
∇
⋅
(
A
→
×
B
→
c
)
+
∇
⋅
(
A
→
c
×
B
→
)
=
∇
⋅
(
A
→
×
B
→
c
)
−
∇
⋅
(
B
→
×
A
→
c
)
=
(
∇
×
A
→
)
⋅
B
→
c
−
(
∇
×
B
→
)
⋅
A
c
=
(
∇
×
A
→
)
⋅
B
→
−
(
∇
×
B
→
)
⋅
A
→
.
{\displaystyle {\begin{aligned}\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )&=\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} _{\mathrm {c} })+\nabla \cdot (\mathbf {\vec {A}} _{\mathrm {c} }\times \mathbf {\vec {B}} )\\[2pt]&=\nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} _{\mathrm {c} })-\nabla \cdot (\mathbf {\vec {B}} \times \mathbf {\vec {A}} _{\mathrm {c} })\\[2pt]&=(\nabla \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} _{\mathrm {c} }-(\nabla \times \mathbf {\vec {B}} )\cdot \mathbf {A} _{\mathrm {c} }\\[2pt]&=(\nabla \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} -(\nabla \times \mathbf {\vec {B}} )\cdot \mathbf {\vec {A}} \!\,.\end{aligned}}}
Drug način, da se označi, da je količina konstanta, je, da se jo kot podpisani indeks doda obsegu operatorja nabla, kot sledi:[ 1] :159, 161–162
∇
→
(
A
→
⋅
B
→
)
A
→
=
A
→
×
(
∇
×
B
→
)
+
(
A
→
⋅
∇
)
B
→
.
{\displaystyle \mathbf {\vec {\nabla }} \left(\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} \right)_{\mathbf {\vec {A}} }=\mathbf {\vec {A}} {\times }\!\left(\nabla {\times }\mathbf {\vec {B}} \right)+\left(\mathbf {\vec {A}} \cdot \nabla \right)\mathbf {\vec {B}} \!\,.}
V preostalem delu tega članka bo po potrebi uporabljen Feynmanov podpisni zapis.
Za skalarni polji
ψ
{\displaystyle \psi \!\,}
,
ϕ
{\displaystyle \phi \!\,}
in vektorski polji
A
→
{\displaystyle \mathbf {\vec {A}} \!\,}
,
B
→
{\displaystyle \mathbf {\vec {B}} \!\,}
obstajajo naslednje identitete odvodov:
∇
→
(
ψ
+
ϕ
)
=
∇
→
ψ
+
∇
→
ϕ
,
{\displaystyle \mathbf {\vec {\nabla }} (\psi +\phi )=\mathbf {\vec {\nabla }} \psi +\mathbf {\vec {\nabla }} \phi \!\,,}
∇
→
(
A
→
+
B
→
)
=
∇
→
A
→
+
∇
→
B
→
,
{\displaystyle \mathbf {\vec {\nabla }} (\mathbf {\vec {A}} +\mathbf {\vec {B}} )=\mathbf {\vec {\nabla }} \mathbf {\vec {A}} +\mathbf {\vec {\nabla }} \mathbf {\vec {B}} \!\,,}
∇
⋅
(
A
→
+
B
→
)
=
∇
⋅
A
→
+
∇
⋅
B
→
,
{\displaystyle \nabla \cdot (\mathbf {\vec {A}} +\mathbf {\vec {B}} )=\nabla \cdot \mathbf {\vec {A}} +\nabla \cdot \mathbf {\vec {B}} \!\,,}
∇
×
(
A
→
+
B
→
)
=
∇
×
A
→
+
∇
×
B
→
.
{\displaystyle \nabla \times (\mathbf {\vec {A}} +\mathbf {\vec {B}} )=\nabla \times \mathbf {\vec {A}} +\nabla \times \mathbf {\vec {B}} \!\,.}
(
A
→
⋅
∇
→
)
ψ
=
A
→
⋅
(
∇
→
ψ
)
,
{\displaystyle (\mathbf {\vec {A}} \cdot \mathbf {\vec {\nabla }} )\psi =\mathbf {\vec {A}} \cdot (\mathbf {\vec {\nabla }} \psi )\!\,,}
(
A
→
⋅
∇
→
)
B
→
=
A
→
⋅
(
∇
→
B
→
)
,
{\displaystyle (\mathbf {\vec {A}} \cdot \mathbf {\vec {\nabla }} )\mathbf {\vec {B}} =\mathbf {\vec {A}} \cdot (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\!\,,}
(
A
→
×
∇
→
)
ψ
=
A
→
×
(
∇
→
ψ
)
,
{\displaystyle (\mathbf {\vec {A}} \times \mathbf {\vec {\nabla }} )\psi =\mathbf {\vec {A}} \times (\mathbf {\vec {\nabla }} \psi )\!\,,}
(
A
→
×
∇
→
)
B
→
=
A
→
×
(
∇
→
B
→
)
.
{\displaystyle (\mathbf {\vec {A}} \times \mathbf {\vec {\nabla }} )\mathbf {\vec {B}} =\mathbf {\vec {A}} \times (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\!\,.}
Za odvod produkta v infinitezimalnem računu ene spremenljivke obstajajo naslednje posplošitve:
∇
→
(
ψ
ϕ
)
=
ϕ
∇
→
ψ
+
ψ
∇
→
ϕ
,
{\displaystyle \mathbf {\vec {\nabla }} (\psi \phi )=\phi \,\mathbf {\vec {\nabla }} \psi +\psi \,\mathbf {\vec {\nabla }} \phi \!\,,}
∇
→
(
ψ
A
→
)
=
(
∇
→
ψ
)
A
→
⊤
+
ψ
∇
→
A
→
=
∇
→
ψ
⊗
A
→
+
ψ
∇
→
A
→
,
{\displaystyle {\begin{aligned}\mathbf {\vec {\nabla }} (\psi \mathbf {\vec {A}} )&=(\mathbf {\vec {\nabla }} \psi )\mathbf {\vec {A}} ^{\top }+\psi \mathbf {\vec {\nabla }} \mathbf {\vec {A}} \\&=\mathbf {\vec {\nabla }} \psi \otimes \mathbf {\vec {A}} +\psi \,\mathbf {\vec {\nabla }} \mathbf {\vec {A}} \!\,,\end{aligned}}}
∇
⋅
(
ψ
A
→
)
=
ψ
∇
⋅
A
→
+
(
∇
→
ψ
)
⋅
A
→
,
{\displaystyle \nabla \cdot (\psi \mathbf {\vec {A}} )=\psi \,\nabla \cdot \mathbf {\vec {A}} +(\mathbf {\vec {\nabla }} \psi )\,\cdot \mathbf {\vec {A}} \!\,,}
∇
×
(
ψ
A
→
)
=
ψ
∇
×
A
→
+
(
∇
→
ψ
)
×
A
→
,
{\displaystyle \nabla \times (\psi \mathbf {\vec {A}} )=\psi \,\nabla \times \mathbf {\vec {A}} +(\mathbf {\vec {\nabla }} \psi )\times \mathbf {\vec {A}} \!\,,}
∇
2
(
ψ
ϕ
)
=
ψ
∇
→
2
ϕ
+
2
∇
→
ψ
⋅
∇
→
ϕ
+
ϕ
∇
→
2
ψ
.
{\displaystyle \nabla ^{2}(\psi \phi )=\psi \,\mathbf {\vec {\nabla }} ^{2\!}\phi +2\,\mathbf {\vec {\nabla }} \!\psi \cdot \!\mathbf {\vec {\nabla }} \phi +\phi \,\mathbf {\vec {\nabla }} ^{2\!}\psi \!\,.}
∇
→
(
ψ
ϕ
)
=
ϕ
∇
→
ψ
−
ψ
∇
→
ϕ
ϕ
2
{\displaystyle \mathbf {\vec {\nabla }} \left({\frac {\psi }{\phi }}\right)={\frac {\phi \,\mathbf {\vec {\nabla }} \psi -\psi \,\mathbf {\vec {\nabla }} \phi }{\phi ^{2}}}\!\,}
∇
→
(
A
→
ϕ
)
=
ϕ
∇
→
A
→
−
∇
→
ϕ
⊗
A
→
ϕ
2
,
{\displaystyle \mathbf {\vec {\nabla }} \left({\frac {\mathbf {\vec {A}} }{\phi }}\right)={\frac {\phi \,\mathbf {\vec {\nabla }} \mathbf {\vec {A}} -\mathbf {\vec {\nabla }} \phi \otimes \mathbf {\vec {A}} }{\phi ^{2}}}\!\,,}
∇
⋅
(
A
→
ϕ
)
=
ϕ
∇
⋅
A
→
−
∇
→
ϕ
⋅
A
→
ϕ
2
,
{\displaystyle \nabla \cdot \left({\frac {\mathbf {\vec {A}} }{\phi }}\right)={\frac {\phi \,\nabla \cdot \mathbf {\vec {A}} -\mathbf {\vec {\nabla }} \!\phi \cdot \mathbf {\vec {A}} }{\phi ^{2}}}\!\,,}
∇
×
(
A
→
ϕ
)
=
ϕ
∇
×
A
→
−
∇
→
ϕ
×
A
→
ϕ
2
,
{\displaystyle \nabla \times \left({\frac {\mathbf {\vec {A}} }{\phi }}\right)={\frac {\phi \,\nabla \times \mathbf {\vec {A}} -\mathbf {\vec {\nabla }} \!\phi \,\times \,\mathbf {\vec {A}} }{\phi ^{2}}}\!\,,}
∇
→
2
(
ψ
ϕ
)
=
ϕ
∇
→
2
ψ
−
2
ϕ
∇
→
(
ψ
ϕ
)
⋅
∇
→
ϕ
−
ψ
∇
→
2
ϕ
ϕ
2
.
{\displaystyle \mathbf {\vec {\nabla }} ^{2}\left({\frac {\psi }{\phi }}\right)={\frac {\phi \,\mathbf {\vec {\nabla }} ^{2\!}\psi -2\,\phi \,\mathbf {\vec {\nabla }} \!\left({\frac {\psi }{\phi }}\right)\cdot \!\mathbf {\vec {\nabla }} \phi -\psi \,\mathbf {\vec {\nabla }} ^{2\!}\phi }{\phi ^{2}}}\!\,.}
Naj je
f
(
x
)
{\displaystyle f(x)\!\,}
funkcija ene spremenljvike od skalarjev do skalarjev
r
→
(
t
)
=
(
x
1
(
t
)
,
…
,
x
n
(
t
)
)
{\displaystyle \mathbf {\vec {r}} (t)=(x_{1}(t),\ldots ,x_{n}(t))\!\,}
parametrizirana krivulja
ϕ
:
R
n
→
R
{\displaystyle \phi \colon \mathbb {R} ^{n}\to \mathbb {R} \!\,}
funkcija od vektorjev do skalarjev in
A
→
:
R
n
→
R
n
{\displaystyle \mathbf {\vec {A}} \colon \mathbb {R} ^{n}\to \mathbb {R} ^{n}\!\,}
vektorsko polje. Obstajajo naslednji posebni primeri odvoda kompozituma za več spremenljivk:
∇
→
(
f
∘
ϕ
)
=
(
f
′
∘
ϕ
)
∇
→
ϕ
,
{\displaystyle \mathbf {\vec {\nabla }} (f\circ \phi )=\left(f'\circ \phi \right)\mathbf {\vec {\nabla }} \phi \!\,,}
(
r
→
∘
f
)
′
=
(
r
→
′
∘
f
)
f
′
,
{\displaystyle (\mathbf {\vec {r}} \circ f)'=(\mathbf {\vec {r}} '\circ f)f'\!\,,}
(
ϕ
∘
r
→
)
′
=
(
∇
→
ϕ
∘
r
→
)
⋅
r
→
′
,
{\displaystyle (\phi \circ \mathbf {\vec {r}} )'=(\mathbf {\vec {\nabla }} \phi \circ \mathbf {\vec {r}} )\cdot \mathbf {\vec {r}} '\!\,,}
(
A
→
∘
r
→
)
′
=
r
→
′
⋅
(
∇
→
A
→
∘
r
→
)
,
{\displaystyle (\mathbf {\vec {A}} \circ \mathbf {\vec {r}} )'=\mathbf {\vec {r}} '\cdot (\mathbf {\vec {\nabla }} \mathbf {\vec {A}} \circ \mathbf {\vec {r}} )\!\,,}
∇
→
(
ϕ
∘
A
→
)
=
(
∇
→
A
→
)
⋅
(
∇
→
ϕ
∘
A
→
)
,
{\displaystyle \mathbf {\vec {\nabla }} (\phi \circ \mathbf {\vec {A}} )=(\mathbf {\vec {\nabla }} \mathbf {\vec {A}} )\cdot (\mathbf {\vec {\nabla }} \phi \circ \mathbf {\vec {A}} )\!\,,}
∇
⋅
(
r
→
∘
ϕ
)
=
∇
→
ϕ
⋅
(
r
→
′
∘
ϕ
)
,
{\displaystyle \nabla \cdot (\mathbf {\vec {r}} \circ \phi )=\mathbf {\vec {\nabla }} \phi \cdot (\mathbf {\vec {r}} '\circ \phi )\!\,,}
∇
×
(
r
→
∘
ϕ
)
=
∇
→
ϕ
×
(
r
→
′
∘
ϕ
)
,
{\displaystyle \nabla \times (\mathbf {\vec {r}} \circ \phi )=\mathbf {\vec {\nabla }} \phi \times (\mathbf {\vec {r}} '\circ \phi )\!\,,}
∇
→
(
r
→
∘
ϕ
)
=
∇
→
ϕ
⊗
(
r
→
′
∘
ϕ
)
.
{\displaystyle \mathbf {\vec {\nabla }} (\mathbf {\vec {r}} \circ \phi )=\mathbf {\vec {\nabla }} \phi \otimes (\mathbf {\vec {r}} '\circ \phi )\!\,.}
Za vektorsko transformacijo
u
→
:
R
n
→
R
n
{\displaystyle \mathbf {\vec {u}} \colon \mathbb {R} ^{n}\to \mathbb {R} ^{n}\!\,}
je:
∇
⋅
(
A
→
∘
u
→
)
=
tr
(
(
∇
→
u
→
)
⋅
(
∇
→
A
→
∘
u
→
)
)
.
{\displaystyle \nabla \cdot (\mathbf {\vec {A}} \circ \mathbf {\vec {u}} )=\operatorname {tr} \left((\mathbf {\vec {\nabla }} \mathbf {\vec {u}} )\cdot (\mathbf {\vec {\nabla }} \mathbf {\vec {A}} \circ \mathbf {\vec {u}} )\right)\!\,.}
Tukaj se vzame sled skalarnega produkta dveh tenzorjev drugega reda, ki ustreza produktu njunih matrik .
∇
→
(
A
→
⋅
B
→
)
=
(
A
→
⋅
∇
)
B
→
+
(
B
→
⋅
∇
)
A
→
+
A
→
×
(
∇
×
B
→
)
+
B
→
×
(
∇
×
A
→
)
=
A
→
⋅
J
→
B
→
+
B
→
⋅
J
→
A
→
=
(
∇
→
B
→
)
⋅
A
→
+
(
∇
→
A
→
)
⋅
B
→
,
{\displaystyle {\begin{aligned}\mathbf {\vec {\nabla }} (\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} )&\ =\ (\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} \,+\,(\mathbf {\vec {B}} \cdot \nabla )\mathbf {\vec {A}} \,+\,\mathbf {\vec {A}} \times (\nabla {\times }\mathbf {\vec {B}} )\,+\,\mathbf {\vec {B}} \times (\nabla \times \mathbf {\vec {A}} )\\&\ =\ \mathbf {\vec {A}} \cdot \mathbf {\vec {J}} _{\mathbf {\vec {B}} }+\mathbf {\vec {B}} \cdot \mathbf {\vec {J}} _{\mathbf {\vec {A}} }\ =\ (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\cdot \mathbf {\vec {A}} \,+\,(\mathbf {\vec {\nabla }} \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} \!\,,\end{aligned}}}
kjer je
J
→
A
→
=
(
∇
→
A
)
⊤
=
(
∂
A
i
/
∂
x
j
)
i
j
{\displaystyle \mathbf {\vec {J}} _{\mathbf {\vec {A}} }=(\mathbf {\vec {\nabla }} \!\mathbf {A} )^{\top }=(\partial A_{i}/\partial x_{j})_{ij}\!\,}
označuje Jacobijevo matriko vektorskega polja
A
→
=
(
A
1
,
…
,
A
n
)
{\displaystyle \mathbf {\vec {A}} =(A_{1},\ldots ,A_{n})\!\,}
.
Druga možnost je raba Feynmanovega podpisnega zapisa:
∇
(
A
→
⋅
B
→
)
=
∇
A
→
(
A
→
⋅
B
→
)
+
∇
B
→
(
A
→
⋅
B
→
)
.
{\displaystyle \nabla (\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} )=\nabla _{\mathbf {\vec {A}} }(\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} )+\nabla _{\mathbf {\vec {B}} }(\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} )\!\,.}
Glej te opombe.[ 7]
Kot posebni primer, ko je
A
→
=
B
→
{\displaystyle \mathbf {\vec {A}} =\mathbf {\vec {B}} \!\,}
:
1
2
∇
(
A
→
⋅
A
→
)
=
A
→
⋅
J
→
A
→
=
(
∇
→
A
→
)
⋅
A
→
=
(
A
→
⋅
∇
)
A
→
+
A
→
×
(
∇
×
A
→
)
=
A
∇
→
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{\displaystyle {\tfrac {1}{2}}\nabla \left(\mathbf {\vec {A}} \cdot \mathbf {\vec {A}} \right)\ =\ \mathbf {\vec {A}} \cdot \mathbf {\vec {J}} _{\mathbf {\vec {A}} }\ =\ (\mathbf {\vec {\nabla }} \mathbf {\vec {A}} )\cdot \mathbf {\vec {A}} \ =\ (\mathbf {\vec {A}} {\cdot }\nabla )\mathbf {\vec {A}} \,+\,\mathbf {\vec {A}} \times (\nabla \times \mathbf {\vec {A}} )\ =\ A\mathbf {\vec {\nabla }} A\!\,.}
Posplošitev formule za skalarni produkt na Riemannove mnogoterosti je definirajoča lastnost Riemannove povezave , ki odvaja vektorsko polje in tako da vektorsko 1-formo .
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{\displaystyle \nabla (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\ =\ (\mathbf {\vec {\nabla }} \mathbf {\vec {A}} )\times \mathbf {\vec {B}} \,-\,(\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\times \mathbf {\vec {A}} \!\,,}
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{\displaystyle \nabla \cdot (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )\ =\ (\nabla \times \mathbf {\vec {A}} )\cdot \mathbf {\vec {B}} \,-\,\mathbf {\vec {A}} \cdot (\nabla \times \mathbf {\vec {B}} )\!\,,}
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{\displaystyle {\begin{aligned}\nabla \times (\mathbf {\vec {A}} \times \mathbf {\vec {B}} )&\ =\ \mathbf {\vec {A}} (\nabla \cdot \mathbf {\vec {B}} )\,-\,\mathbf {\vec {B}} (\nabla \cdot \mathbf {\vec {A}} )\,+\,(\mathbf {\vec {B}} \cdot \nabla )\mathbf {\vec {A}} \,-\,(\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} \\[2pt]&\ =\ \mathbf {\vec {A}} (\nabla \cdot \mathbf {\vec {B}} )\,+\,(\mathbf {\vec {B}} \cdot \nabla )\mathbf {\vec {A}} \,-\,(\mathbf {\vec {B}} (\nabla \cdot \mathbf {\vec {A}} )\,+\,(\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} )\\[2pt]&\ =\ \nabla \cdot \left(\mathbf {\vec {B}} \mathbf {\vec {A}} ^{\top }\right)\,-\,\nabla \cdot \left(\mathbf {\vec {A}} \mathbf {\vec {B}} ^{\top }\right)\\[2pt]&\ =\ \nabla \cdot \left(\mathbf {\vec {B}} \mathbf {\vec {A}} ^{\top }\,-\,\mathbf {\vec {A}} \mathbf {\vec {B}} ^{\top }\right)\!\,,\end{aligned}}}
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{\displaystyle {\begin{aligned}\mathbf {\vec {A}} \times (\nabla \times \mathbf {\vec {B}} )&\ =\ \nabla _{\mathbf {\vec {B}} }(\mathbf {\vec {A}} \cdot \mathbf {\vec {B}} )\,-\,(\mathbf {\vec {A}} {\cdot }\nabla )\mathbf {\vec {B}} \\[2pt]&\ =\ \mathbf {\vec {A}} \cdot \mathbf {\vec {J}} _{\mathbf {\vec {B}} }\,-\,(\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} \\[2pt]&\ =\ (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\cdot \mathbf {\vec {A}} \,-\,\mathbf {\vec {A}} \cdot (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\\[2pt]&\ =\ \mathbf {\vec {A}} \cdot (\mathbf {\vec {J}} _{\mathbf {\vec {B}} }\,-\,\mathbf {\vec {J}} _{\mathbf {\vec {B}} }^{\top })\!\,,\end{aligned}}}
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{\displaystyle {\begin{aligned}(\mathbf {\vec {A}} \times \nabla )\times \mathbf {\vec {B}} &\ =\ (\mathbf {\vec {\nabla }} \mathbf {\vec {B}} )\cdot \mathbf {\vec {A}} \,-\,\mathbf {\vec {A}} (\nabla \cdot \mathbf {\vec {B}} )\\[2pt]&\ =\ \mathbf {\vec {A}} \times (\nabla \times \mathbf {\vec {B}} )\,+\,(\mathbf {\vec {A}} \cdot \nabla )\mathbf {\vec {B}} \,-\,\mathbf {\vec {A}} (\nabla \cdot \mathbf {\vec {B}} )\!\,,\end{aligned}}}
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{\displaystyle (\mathbf {\vec {A}} \times \nabla )\cdot \mathbf {\vec {B}} \ =\ \mathbf {\vec {A}} \cdot (\nabla {\times }\mathbf {\vec {B}} )\!\,.}
Upoštevati je treba, da je matrika
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{\displaystyle \mathbf {\vec {J}} _{\mathbf {\vec {B}} }\,-\,\mathbf {\vec {J}} _{\mathbf {\vec {B}} }^{\top }\!\,}
poševnosimetrična .